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9y^2-37y=-36
We move all terms to the left:
9y^2-37y-(-36)=0
We add all the numbers together, and all the variables
9y^2-37y+36=0
a = 9; b = -37; c = +36;
Δ = b2-4ac
Δ = -372-4·9·36
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-\sqrt{73}}{2*9}=\frac{37-\sqrt{73}}{18} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+\sqrt{73}}{2*9}=\frac{37+\sqrt{73}}{18} $
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